(3^x-5)=(9^x+4)

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Solution for (3^x-5)=(9^x+4) equation: 



(3^x-5)=(9^x+4)

We move all terms to the left:

(3^x-5)-((9^x+4))=0

We get rid of parentheses

3^x-((9^x+4))-5=0



We calculate terms in parentheses: -((9^x+4)), so:

(9^x+4)

We get rid of parentheses

9^x+4

Back to the equation:

-(9^x+4)



We get rid of parentheses

3^x-9^x-4-5=0

We add all the numbers together, and all the variables

3^x-9^x-9=0

We move all terms containing x to the left, all other terms to the right

3^x-9^x=9

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